VIP members get additional benefits.Login to The Constructor to ask questions, answer people’s questions, write articles & connect with other people. TEST DATA FOR MATERIALS . workability, bleeding and finishing qualities.Mix is cohesive, workable and had a true slump of about 25 mm and it is free from segregation and bleeding.So modifications are needed in trial mix 1 to arrive at the desired workability.To increase the workability from 25 mm to 50-75 mm an increase in water content by +3% is to be made.The corrected water content = 191.6 x 1.03 = 197.4 kg.As mentioned earlier to adjust fresh concrete properties the water cement ratio will not be changed. It is responsible mainly for the porosity of the hardest cement paste.It was first developed by Duff A. Abrams in 1918. In the present example water cement ratio is raised to 0.55 from 0.5.An increase of 0.05 in the w/c will entail a reduction in the coarse aggregate fraction by 0.01.Hence the coarse aggregate as percentage of total aggregate = 0.558 – 0.01 = 0.548= 1 – [{(358.9/(3.15 x 1000)} + (197.4/1000)] =0.688 mMass of coarse aggregate = 0.688 x 0.548 x 2.84 x 1000 = 1070.75 kg/mMass of fine aggregate = 0.688 x 0.452 x 2.64 x 1000 = 821 kg/mFor casting trial -3, mass of ingredients required will be calculated for 4 no’s cube assuming 25% wastage.Volume of concrete required for 4 cubes = 4 x (0.15Mix is stable, cohesive, and workable and had a true slump of about 75 mm.So , it has achieved desired workability by satisfying the requirement of 50-75 mm slump value .In this case water / cement ratio is decreased by 10% keeping water content constant.A reduction of 0.05 in w/c will entail and increase of coarse aggregate fraction by 0.01.= 1 – [{438.7/(3.15 x 1000)} + (197.4/1000)] = 0.664 mMass of coarse aggregate = 0.664 x 0.568 x 2.84 x 1000 = 1071.11 kg/mMass of fine aggregate = 0.664 x 0.432 x 2.64 x 1000 = 757.28 kg/mFor casting trial -4, mass of ingredients required will be calculated for 4 no’s cube assuming 25% wastage.Volume of concrete required for 4 cubes = 4 x (0.15A local correction due to moisture condition of aggregate is again applied on this proportions. In this civil engineering article, the calculation is done to determine the quantity of water for M25 grade of concrete. While going to build up concrete construction, sufficient amount of water is required. We know that Concrete is a mixture of Cement, Sand, Aggregate and water. Cement, Sand, Coarse aggregate, and water with a suitable proportion of water.. All of these components are mixed according to batching or Concrete grade table, Maybe M10, M20, M25, M30, etc. For proper workability, the water-cement ratio varies from 0.4–0.6. So 1.54 Cum of dry materials (cement, sand and aggregate) is required to produce 1 Cum of concrete. More water cement ratio produces porousness in concrete.Water–cement ratio is normally retained as 0.45 to 0.60. Component of Concrete . So, concrete mix design can be stated as Concrete Mix = Cement:Sand:Aggregates.The concrete mix design involves various steps, calculations and laboratory testing to find right mix proportions. VIP members get additional benefits.Lost your password? (a) Characteristic compressive strength required in the field at 28 days grade designation — M 25(d) Degree of workability required at site — 50-75 mm (slump)(e) Degree of quality control available at site — As per IS:456(f) Type of exposure the structure will be subjected to (as defined in IS: 456) — Mild(d) Aggregate are assumed to be in saturated surface dry condition.Himsworth constant for 5% risk factor is 1.65. With this proportion, concrete is manufactured and tested for fresh concrete properties requirement i.e. Please enter your email address. Same, Different grades of Concrete Mix design need a different quantity of water. This process is usually adopted for structures which requires higher grades of concrete such as M25 and above and large construction projects where quantity of concrete consumption is huge..Benefits of concrete mix design is that it provides the right proportions of materials, thus making the concrete construction economical in achieving required strength of structural members. Quantity of water = 0.42 x 50 = 21 Liters (1 bag cement = 50 Kg) So the required quantity of water is 21 Liters per cement bag. The quantity of water differs according to diverse concrete grades.In this civil engineering article, the calculation is done to determine the quantity of water for M25 grade of concrete.So, for 9.51 bags, the required quantity of cement = 50 x 9.51 = 476 kgThe water–cement ratio means the proportion of the weight of water to the weight of cement utilized in a concrete mix.The water to cement ratio is measured by dividing the water in one cubic yard of the mix ( in pounds) with the cement in the mix (in pounds). I STIPULATIONS FOR PROPORTIONING. Water-Cement ratio in concrete possesses a great rank in acquiring desired strength of concrete. You will receive a link and will create a new password via email.Sorry, you do not have permission to ask a question, You must login to ask question. In below ‘M’ refers to Mix and value behind M refers to Remember, the above-mentioned values are nominal and may vary depending upon the moisture content present in sand, cement and aggregate. The above is a trial design mix. Provided that we Assume the necessary cement volume as 50kg, Required measure of water = W/C Ratio X Cement Volume Subsequently, Required measure of water = … Volume of sand & aggregate required for 50 kg cement bag for M25 grade of concrete.